I was trying to calculate the maximum product that can be achieved when traveling from the top left of a 2D array to the bottom right. I know there is a solution here that uses dynamic programming in a bottom up manner (i.e. iterative for loops here: https://www.byte-by-byte.com/matrixproduct/) I was attempting to do this using ..

#### Category : backtracking

Im trying to make a sudoku solver algorithm to practice recursion and backtracking, so made this function ‘backtrack’ which is the main function that’s supposed to solve it , and four other ‘utility/helper’ functions;the first one is ‘getSubGrid’ which returns the subgrid where the current number belongs,and then ‘getColumn’ which returns the column where the ..

In trying to solve the following problem: Generate all combinations of an array of string. Ex: Input: [‘A’, ‘T’, ‘C’, ‘K’] Output: [ ‘ATCK’, ‘ATC’, ‘ATK’, ‘AT’, ‘ACK’, ‘AC’, ‘AK’, ‘A’, ‘TCK’, ‘TC’, ‘TK’, ‘T’, ‘CK’, ‘C’, ‘K’, ” ] I have the following code: function getSpellableWords(arr) { const res = []; // helper(arr, res, ..

let row = this.findEmpty(puzzleString)[0]; let col = this.findEmpty(puzzleString)[1]; let i = this.findEmpty(puzzleString)[2]; if(!this.findEmpty(puzzleString)) return puzzleString for(let num = 1; num < 10; num++){ if(this.checkValue(puzzleString, row, col, num)){ puzzleString[i] = num; this.solve(puzzleString) } } findEmpty(puzzleString) iterates over the puzzle string and returns the row (A-I), column (1-9), and index of a blank grid. checkValue() contains 3 ..

I am trying to implement a backtracking algorithm in JS to find the minimum value possible by swapping k digits. I can’t see why my code doesn’t work. If I log out the values for num, it goes down to 159 but that doesn’t get returned as the minSoFar, for some reason. Any ideas please? ..

On a 2-dimensional grid, there are 4 types of squares: 1 represents the starting square. There is exactly one starting square. 2 represents the ending square. There is exactly one ending square. 0 represents empty squares we can walk over. -1 represents obstacles that we cannot walk over. Return the number of 4-directional walks from the starting ..

I wanted to implement a question where we find paths in a maze from (0,0) cell to (m-1,n-1) cell with having some obstacles in between. I have used recursive backtracking algorithm to solve the problem and I just wanted to make some kind of visualization where we can see how the path is been taken ..

const N = 4; const fourbyfour = [ [1, 0, 0, 4], [3, 4, 1, 2], [2, 1, 4, 3], [4, 3, 2, 1], ]; function solve(board) { for (let i = 0; i < N; i++) { for (let j = 0; j < N; j++) { if (board[i][j] === 0) { for (let ..

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